Which of the following is the nth taylor polynomial tn(x) for f(x)=ln(1−x) based at b=0? tn(x) = −x + 1 2 x2 − 1 3 x3−+ 1 n xn tn(x) = −x − x2 − 1 2 x3−− 1 n−1 xn tn(x) = −x − 1 2 x2 − 1 3 x3−− 1 n xn tn(x) = −x − 1 2! x2 − 1 3! x3−− 1 n! xn find the smallest value of n such that taylor's inequality guarantees that |tn(x)−ln(1−x)|< 0.01 for all x in the interval i= − 1 2 , 1 2

dont trust me im no expert these losers made me fail a test bro this sucks

step-by-step explanation:

you need to add a picture

choose (5, 1.5) and (-1.5,-3.5)

step-by-step explanation:

5 - 1.5 =3.5

-1.5 - (-3.5) = 2

3.5 + 2 =5.5

hope this !

1 ?

step-by-step explanation:

u said 1+1+1+1+1+1+1+1+1+1+1+1*0 so ur adding 1 but then multiplying by 0 so its 0 but then u said 1*0+1 so now ur adding 1 so the answer is juan ?

~leah