Fifty-three percent of employees make judgements about their co-workers based on the cleanliness of their desk. you randomly select 8 employees and ask them if they judge co-workers based on this criterion. the random variable is the number of employees who judge their co-workers by cleanliness. which outcomes of this binomial distribution would be considered unusual?

No employees or 8 employees judging co-workers based on the cleanliness of their desk would be considered unusual outcomes.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

The standard deviation of the binomial distribution is:

Outcomes are unusual when they are more than 2.5 standard deviations of the mean.

In this problem, we have that:

So

No employees or 8 employees judging co-workers based on the cleanliness of their desk would be considered unusual outcomes.

nothjing

step-by-step explanation:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3