Of all sixth graders, 70% sent a text
message yesterday. ten trials of a
simulation are conducted and the
data are recorded below.
62072, 34570, 80983, 04292, 83150,
36330, 96268, 14077, 77985, 13511
the numbers 0 through 6 represent
students who sent a text yesterday,
and the numbers 7 through 9
represent students who did not send
a text yesterday.
based on the simulated data, what
is the probability that 3 or more
of a group of 5 students randomly
selected will send a text today?
explain.

56

step-by-step explanation:

the degrees would remain the same ( the number to the left of the decimal point.

the multiply the decimal by 60 to get the minutes and use the numbers to the left of the decimal point.

then multiply the decimal portion of that by 60 for the seconds and round off as needed.

39 .956652

the 39 remains the degrees.

the minutes = 0.956652 x 60 = 57.39912

the minutes = 57

the seconds = 0.39912 x 60 = 23.95 = 24 ( rounded to nearest tenth)

so 39.956652 = 39 degrees, 57 minutes and 24 seconds

-75.159809

the -75 remains the degrees

the minutes = 0.159809 x 60 = 9.58854

the minutes = 9

the seconds = 0.58854 x 60 = 35.31, rounded to nearest tenth = 35.3 seconds

so -75.159809 = -75 degrees, 9 minutes and 35.3 seconds.

the first coordinate is north or south, since it it positive it is north.

the second number is east or west, because it is negative it is west.

39 degrees, 57 minutes and 24 seconds n

-75 degrees, 9 minutes and 35.3 seconds w