Acode is made up of a letter (a–z) and two digits (0–9). the digit can be repeated. how many possible codes exist? 2600 260 46 28

2600.

Step-by-step explanation:

There are 26 letters.

Also there are 10P2 permutations of the digits 0-9

10P2 =  10!/(10-2)! = 90.

There are 10 repeated digits.

So the number of possible codes are 26*(90 + 10)

= 2600.

c.

step-by-step explanation:

answer: c

because if you look at the chart you can see a pattern and compare it to the question he simplify out your

but i think the formula is f(x)=6x