If p(a) = 0.3, p(b) = 0.2, and p(a ∩ b) = 0.1, determine the following probabilities: a. p(a′) b. p(a ∪ b) c. p(a′ ∩ b) d. p(a ∩ b′) e. p[(a ∪ b)′] f. p(a′ ∪ b)

a.

b.

c. By the law of total probability,

so that

d. Similar to (c); we have

e.

f. By DeMorgan's law,

answer

the correct answer is

explanation

the given function is

the excluded values are obtained by solving:

we factor to obtain:

the excluded values are

4.5%

step-by-step explanation: