He number of square feet per house are normally distributed with an unknown population mean and standard deviation. if a random sample of 47 houses is taken to estimate the mean house size, what t-score should be used to find a 80% confidence interval estimate for the population mean?

1.300228

Step-by-step explanation:

The t-score we use for the confidence interval is two-tailed , i.e. the  t-score should be used to find a () is given by :-

, where n is the sample size.

Given : Level of confidence:

Significance level :

Sample size : n= 47

Then, degree of freedom :

Now by using standard normal t-distribution table,

Hence, the t-score should be used to find a 80% confidence interval estimate for the population mean = 1.300228

the first one, all those points on the line just make a strait line.