Number of cars parked at any one time = 48
required area of service garage?
would it be 24,000 ft?

 24,000

Step-by-step explanation:

The instructions state to multiply the number of cars by 250 ft² and then double it (multiply by 2).

48 cars × 250 ft² × 2 = 24,000 ft²

answer: 4/6 =5/7.5

step-by-step explanation: it is based on scale and the scale between the two is 1.25. the answer is correct but i dont know if i explained it right

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).