Question 3. find the following gcd and lcm: (3.a) gcd(343, 550), lcm(343, 550).|| (3.b) gcd(89, 110), lcm(89, 110). (3.c) gcd(870, 222), lcm(870, 222).

(3.a) GCD(343,550)=1

LCM(343, 550)=188650

(3.b) GCD(89, 110)=1

LCM(89, 110)=9790

(3.c) GCD(870, 222)=6

LCM(870, 222)=32190

Step-by-step explanation:

(3.a) GCD(343,550), LCM(343, 550).

343=7×7×7

550=5×5×2×11

GCD(343,550)=1

LCM(343,550)=7×7×7×5×5×2×11=188650

(3.b) GCD(89, 110), LCM(89, 110).

89=1×89

110=5×2×11

GCD(89, 110)=1

LCM(89, 110)=89×5×2×11=9790

(3.c) GCD(870, 222), LCM(870, 222).

870=2×3×5×29

222=2×3×37

GCD(870, 222)=2×3=6

LCM(870, 222)=2×3×5×29×37=32190

95.03 is the answer. hope this !

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages