Arandom sample of 1,250 couples was asked the question, "how many children presently reside in your household? "
number of children—frequency
0——250

2——560
3 ——201
5 or more ——59
what number of children occurred the least frequently? calculate this percent
a) 2, 55.2%
b)5 or more, 4.72%
c)5 or more, 11.91%
d)4.21.67%

Option B

4.72%

Step-by-step explanation:

We know that the total number of couples surveyed was 1250

Now identify the lowest frequency and divide it by the total of couples surveyed

The lowest frequency is that corresponding to 5 children or more.

The percentage is:

Only 4.72% of couples surveyed have 5 children or more

The answer is the option B

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w

false

step-by-step explanation:

false : it can not go to 9 the highest that part can go is 7

here is your proof