Mathematics, 31.08.2019 03:30 ineedhelpireallydo

(a) each person has two parents, four grandparents, eight great-grandparents, and so on. by summing a geometric sequence, find the total number of ancestors a person has going back (1) five generations, (2) 10 generations. normal growth pattern for children aged 3-11 follows an arithmetic sequence. given a child measures 98.2 cm at age 3, and 109.8 cm at age 5, what is the common difference of the arithmetic sequence? what would the child's height at age 8 be?

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Answer from: Serenitybella

The person has62 ancestors going back five generations.

The person has 2046 ancestors going back ten generations.

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The child's height at age 8 would be 127.2 cm.

Step-by-step explanation:

The first sequence is a geometric sequence.

In a geometric sequence, each term is found by multiplying the previous term by a constant r.

We write a geometric sequence like this:

${a, ar, ar^{2}, ar^{3},...}$

Where a is the first term and r is the commom factor.

The sum of the first n elements of a geometric sequence is:

$S = \frac{a(1 - r^{n})}{1-r}$

So, for the first exercise, our geometric sequence is:

{2,4,8,...},

so a = 2 and r = 2.

1)Find the total number of ancestors a person has going back five generations

S when n = 5, so:

$S = \frac{a(1 - r^{n})}{1-r} = \frac{2*(1-2^{5})}{1-2} = 62$

The person has 62 ancestors going back five generations.

2) Going back 10 generations:

S when n = 10, so:

$S = \frac{a(1 - r^{n})}{1-r} = \frac{2*(1-2^{10})}{1-2} = 2046$

The person has 2046 ancestors going back ten generations.

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The following question is related to an arithmetic sequence:

An arithmetic sequence is a sequence of numbers such that the difference of any two successive members of the sequence is a constant.

If the first term of an arithmetic sequence is a1 and the common difference is d, then the nth term of the sequence is given by:

$a_{n} = a_{1} + (n-1)d$ .

We have the following sequence

$98.2, a_{2}, 109.8, a_{4}, a_{5}, a_{6}$ , in which $a_{6}$ is the child's height at age 8.

We have that:

$d = \frac{109.8 - 98.2}{2} = 5.8$

$a_{6} = a_{1} + 5d = 98.2 + 5*5.8 = 127.2$ .

The child's height at age 8 would be 127.2 cm.

Answer from: Quest

a is the correct

And do not get it wrong . this is a quiz and im struggling ! ☹️

Answer from: Quest

solution:

the given function is ,

$f(x) = 4 x^3 - 72 x^2 + 320 x,$

= $4x( x^2- 18 x + 80)\\\\ 4 x(x^2-10 x -8 x + 80) \\\\ 4 x[(x-10)(x-8)]$

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

$f(x) = a x^3+ b x^2 + c x+d,$

sum of the roots = a + b +c= 0+8+10=18= $\frac{-b}{a}$

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 = $\frac{c}{a}$

product of roots = a b c = 0= $\frac{d}{a}$

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function $f(x) = 4 x^3 - 72 x^2 + 320 x,$ is given by entry and exit route of this hall.