The perimeter of a rectangle is p= 2l +2w, where l is the length and w is the width. if the perimeter is 200 feet and the length is 40 feet more than the width, what are the dimensions?

Length - 70

Width - 30

Step-by-step explanation:

Let the width be x

Length is 40 more than width which makes length = x + 40

Perimeter = 2L + 2W

2(x + 40) + 2(x)

Open brackets

2x + 80 + 2x = 4x + 80

Perimeter = 200

200 = 4x + 80

4x = 200 - 80

4x = 120

x = 120/4

x = 30

Width = 30

Length = x + 40 = 70

Give brainliest

answer:

your answer is: c. 196 7/8 in^3.

y + 11 = (1/4)(x + 16)

step-by-step explanation: