Write the equation of the line that passes through (3, −2) and has a slope of 4 in point-slope form. (2 points)
a
y + 2 = 4(x − 3)
b
y − 3 = 4(x + 2)
c
x − 3 = 4(y + 2)
d
x + 2 = 4(y − 3)

A. y+2=4(x-3)

Step-by-step explanation:

To write an equation in slope-point form you write as;

y-y₁=m(x-x₁) where m is slope of line and (x₁,y₁) is one point on the line

In this question you are given m=4 and (x₁,y₁) as (3,-2) then the equation is

y-y₁=m(x-x₁)substitute values

y--2=4(x-3)simplify further

y+2=4(x-3)

cosine

step-by-step explanation:

step-by-step explanation:

let

we know that

the y-intercept is the y-coordinate of the point when the value of x is equal to zero

so

the y-coordinate of the point a is the y-intercept

the answer part a) is

the value of y-intercept is

part b) find the slope m

we know that

the value of the slope is equal to

substitute the values

therefore

the answer part b) is

the value of the slope is equal to

the general answer is

the slope is

the value of y-intercept is