Δefi is dilated by a scale factor of one half with the center of dilation at point f. then, it is reflected over line a to create δhfg. based on these transformations, which statement is true?
line segments eg and hi intersect at point f, forming triangles efi and hfg. line a intersects with both triangles at point f.
segment fh = two segment fe, segment fg = two segment fi, and segment hg = two segment ei; δefi ~ δhfg
two segment fh = segment fe, two segment fg = segment fi, and two segment hg = segment ei; δefi ~ δhfg
segment fh = two segment fi, segment fg = two segment fe, and segment hg = two segment ei; δefi ~ δgfh
two segment fh = segment fi, two segment fg = segment fe, and two segment hg = segment ei; δefi ~ δgfh

  two segment FH = segment FE, two segment FG = segment FI, and two segment HG = segment EI; ΔEFI ~ ΔHFG

Step-by-step explanation:

Dilation by a factor of 1/2 means twice the reduced segment is equal to the original.

The reflection maps E'F to HF, so ΔEFI ~ ΔHFG.

Option B.

Step-by-step explanation:

It is given that ΔEFI is dilated by a scale factor of one half with the center of dilation at point F. Then, it is reflected over line a to create ΔHFG.

Multiply both sides by 2.

Similarly,

Multiply both sides by 2.

And,

Multiply both sides by 2.

By SSS property of similarity,

ΔEFI ~ ΔGFH

Since, , , , therefore ΔEFI ~ ΔGFH.

Therefore, the correct option is B.

attachment?

step-by-step explanation:

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation: