Whats process in proving that the solution of an inequality is valid.

the solution of an inequality is an interval, i.e. a range.

to prove that the interval found as solution, you must consider several cases.

1) in the case that the ineguailty is ≥ or ≤, first use the limits of the interval to prove they are valid solutions. this is, replace the limit values, one at a time, and verifiy the inequality.

2) if the sign is ≥ or > use a value to the right of the limit value to show that the values to the right are solution, and use a value to the left to show that they are not solution.

3) if the sign is ≤ or < , use a value to the left of the limit value to show that it is a solution and a value to the right of the limit value to show that it is not a solution.

step-by-step explanation:

the discriminant is 64 + 4*1*12 = 112

this is prime.

step-by-step explanation:

b.my answer is b.

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