What is the solution to 0.6(24x-32)=0.8(24-6x)?

Step-by-step explanation:

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Linear Equation Problems

Value of the unknown quantity for which from given equation we get true numerical equality is called root of that equation. Two equations are called equivalent when the multitudes of their roots match, the roots of the first equation are also roots of the second and vice versa. The following rules are valid:

1.If in given equation one expression is substituted with another identity one, we get equation equivalent to the given.

2.If in given equation some expression is transferred from one side to the other with contrary sign, we get equation equivalent to the given.

3.If we multiply or divide both sides of given equation with the same number, different from zero, we get equation equivalent to the given.

Equation of the kind \displaystyle ax + b = 0ax+b=0, where \displaystyle a, ba,b are given numbers is called simple equation in reference to the unknown quantity \displaystyle xx.

Problem 1 Solve the equation:

A) 16x + 10 – 32 = 35 – 10x - 5

B) \displaystyle y + \frac{3}{2y} + 25 = \frac{1}{2}y + \frac{3}{4}y – \frac{5}{2}y + y + 37y+

2y

3

+25=

2

1

y+

4

3

y–

2

5

y+y+37

C) 7u – 9 – 3u + 5 = 11u – 6 – 4u

Solution:

A)We do some of the makred actions and we get

16x – 22 = 30 – 10x

After using rule 2 we find 16x + 10x = 30 + 22

After doing the addition 26x = 52

We find unknown multiplier by dividing the product by the other multiplier.

That is why \displaystyle x = \frac{52}{26}x=

26

52

Therefore x = 2

B) By analogy with A) we find:

\displaystyle y\left(1 + \frac{3}{2}\right) + 25 = y\left(\frac{1}{2} + \frac{3}{4} – \frac{5}{2} + 1\right) + 37 \Leftrightarrowy(1+

2

3

)+25=y(

2

1

+

4

3

–

2

5

+1)+37⇔

\displaystyle \frac{5}{2}y + 25 = -\frac{1}{4}y + 37 \Leftrightarrow \frac{5}{2}y + \frac{1}{4}y = 37 - 25 \Leftrightarrow

2

5

y+25=−

4

1

y+37⇔

2

5

y+

4

1

y=37−25⇔

\displaystyle \frac{11}{4}y = 12 \Leftrightarrow y = \frac{12.4}{11} \Leftrightarrow y = \frac{48}{11}

4

11

y=12⇔y=

11

12.4

⇔y=

11

48

C) 4u – 4 = 7u – 6 <=> 6 – 4 = 7u – 4u <=> 2 = 3u <=> \displaystyle u = \frac{2}{3}u=

3

2

sorry can't

step-by-step explanation:

i googled though and something came up but it was in science langueage not common english sooo

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.