Mathematics, 04.09.2019 05:20 Niaax7803

Mrs. allans car uses 8 gallons of gas for a 224-mile trip. mrs. owens car uses 6 gallons of gas for a 210-mile trip.
parta: what are the unit rates for each cars gas usage?
partb: whose car has better gas mileage?
partc: at these rates, how many gallons of gas would each car use if both cars traveled 560 miles? explain
answer what you can . it is appreciated

Mrs.allans car uses 8 gallons of gas for a 224-mile trip. mrs.owens car uses 6 gallons of gas for a

Answers: 2

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Answer from: kaitlyn7077

A. Mileage is read in Miles per gallons

B.Hence ownens car has a better mileage

C. Allans CAr : 20 gallons

Owens car : 16 Gallons

Step-by-step explanation:

Allans Car

Distance traveled = 224 miles

Fuel consumed = 8 gallons

Distance covered in 1 gallon = $\frac{224}{8}$ = 28

Hence mileage is 28 miles per gallon

Owens Car

Distance traveled = 210 miles

Fuel consumed = 6 gallons

Distance covered in 1 gallon = $\frac{210}{6}$ = 35

Hence mileage is 35 miles per gallon

Hence ownens car has a better mileage

If the Distance traveled by both car is 560 miles

Allans car

Fuel consumed = $\frac{560}{28}$ = 20 gallons

Owens car

Fuel consumed = $\frac{560}{35}$ = 16 gallons

Answer from: aaronscott6474

A.Rate of Mrs. Allan's car=28 mile/gallon

Rate of Mrs. Owen's car=35 mile/gallon

B.Mrs. Owen's car

C.Mrs.Allen's car used gas for 560 miles=20 gallons

Mrs.Owen's car used gas for 560 miles=16 gallons

Step-by-step explanation:

We are given that

Mrs. Allan's car uses 8 gallons of gas for 224 mile tripe.

Mrs. Owens car uses 6 gallons of a gas for 210 mile tripe.

A.Rate= $\frac{Distance\;traveled}{Gas;used}$

Rate of Mrs. Allan's car= $\frac{224}{8}=28 mile/gallon$

Rate of Mrs. Owen's car= $\frac{210}{6}=35 mile/gallon$

B.Mrs.Allan's car travel in 1 gallon of gas =28 miles

Mrs. Owen' s car travel in one gallon of gas=35 miles

Therefore, Mrs. Owen's car travel large distance in one gallon of gas.Hence, it is better.

C.If distance traveled by the cars=560 miles

Mrs. Allen's car used gas for 28 mile=1 gallon

Mrs. Allen's car used gas for 1 mile= $\frac{1}{28}$

Mrs.Allen's car used gas for 560 mile= $\frac{560}{28}=20 gallons$

Mrs.Allen's car used gas for 560 miles=20 gallons

Mrs.Owen's car used gas for 35 miles=1 gallon

Mrs. Owen's car used gas for 1 mile= $\frac{1}{35}$

Mrs. Owen's car used gas for 560 miles= $\frac{560}{35}=16 gallons$

Mrs.Owen's car used gas for 560 miles=16 gallons

Answer from: Quest

step-by-step explanation:

Answer from: Quest

900 degrees

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