|-4a+10|=2 show step by step work or answer

|-4a+10|=2 when a = 2 or a = 3.

Step-by-step explanation:

Your problem is a modular function problem

Modular function

The modulus of a value is the distance of the value to the origin.

It is quite helpful to start this kind of problem from a simple example.

|a| = b is if a = b or if a = -b. |x| = 2 if x = 2 or if x = -2. In both cases, the distance to the origin is 2.

So in your question, we have:

a = -4a + 10

b = 2

Now we have to apply both cases.

Solution 1: |a| = b if a = b

a = b

-4a + 10 = 2

-4a = -8 *(-1)

4a = 8

a = 2

Solution 1: |a| = b if a = -b

a = -b

-4a + 10 = -2

-4a = -12 *(-1)

4a = 12

a = 3

So, |-4a+10|=2 when a = 2 or a = 3.

b

step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?