Ablock with a mass m = 5 kg slides down an inclined plane with an angle θ = 37°. the block maintains a constant acceleration a = 5.6 m/s2 . (sin37° = 0.6, cos37° = 0.8). the coefficient of kinetic friction between the block and the inclined surface is 0.05. what is the normal force on the block?

1148.6 N

Step-by-step explanation:

Given

mass of block =5 kg

Inclination angle

constant acceleration(a)

be the coefficient of kinetic friction =0.05

we know friction force

forces acting on block is down the inclined  plane

friction force acting parallel to surface opposing

Therefore

N=1148.6 N

a framing bias

step-by-step explanation:

rodrigo is subject to a framing bias i believe.