Refer to the following information from a frequency distribution for heights of college women recorded to the nearest inch: the first two class midpoints are 62.5" and 65.5". what are the class limits for the lowest class?

61"-64"

Step-by-step explanation:

There is one thing I'm assuming in order to calculate this, and it is that the size of the classes is homogeneous, meaning, that all clases have the same size from the lower limit to the upper limit.

So, you are given the midpoints of the two lowest classes. If you check the crude graph I drew on paint, you can see that the midpoint is exactly what it sounds, the middle point of each class.

If the classes have the same size, then the "distance" from one midpoint to the next one is 2 times half the size of a class (because you go from mid to upper limit, and then from the lower limit to mid, as you can see in the graph)

if you subtract the greater midpoint from the lower one, you have that distance:

65.5"-62.5"=3=2*halfclass

1.5"=halfclass

Now if you subtract the value of halfclass from a midpoint, you get the lower limit, and if you add it you get the upper limit:

Lower limit = 62.5"-1.5"=61"

Upper Limit = 62.5"+1.5"=64"

not sure but it may be b, as i said i'm not sure.

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752