What is the factorization of the trinomial below/ 3x^2-21x+30?

3*(x-5)*(x-2)

Step-by-step explanation:

To factorize 3*x^2 - 21*x + 30 we can find the roots with the quadratic formula:

The factorized form is , that is,  3*(x-5)*(x-2)

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

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put in or use mine

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

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