Each student in a course needs to submit 3 lab assignments and take 2 tests. design a program to do the following. ask the user to enter 3 lab scores and 2 test scores. calculate and display the lab average and the test average. also calculate and display the course grade, which equals 55% of the lab average plus 45% of the test average.

Enter the value of the score in the laboratory 1

L1 = digited value.

Enter the value of the score in laboratory 2

L2 = digited value.

Enter the value of the score in laboratory 3

L3 = digited value.

Enter the value of the test score 1

P1 = digited value.

Enter the value of the test score 2

P2 = digited value.

Laboratory Average = (L1 + L2 + L3) / 3

Print "Laboratory Average"

Test Average = (P1 + P2) / 2

Print "Test Average"

Course qualification = 0.55 * (Laboratory Average) + 0.45 * (Test Average)

print "Course qualification"

Step-by-step explanation:

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.