Given that the restriction of the cosine function cos to i : = [0, 1] is strictly decreasing and that cos 0 = 1, cos 7 = -1, let ) : = (-1,1), and let arccos: j r be the function inverse to the restriction of cos to i. show that arccos is differentiable on (-1, 1) and d acrccos y = (-1)/(1-2)2 for ye (-1, 1). show that arccos is not differentiable at -1 and 1.

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.

b.-4 units

all you   do is count how many times you move

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1

the domain of a function is the set of input values, x , for which a function is defined. the domain is shown in the left oval in the picture below. the function provides an output value, f(x) , for each member of the domain.