Find 3 consecutive even interferes such that their sum is 42

12, 14, and 16

Step-by-step explanation:

These kinds of problems can be written as the equation x + (x + 2) + (x + 4) = s, where x = first integer and s = total.

Plug in s: x + (x + 2) + (x + 4) = 42

Associative property of addition: x + x + 2 + x + 4 = 42

Combine like terms: 3x + 6 = 42

Subtract: 3x = 36

Divide: x = 12

This means that the first integer is 12, and the rest are 14 and 16.

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

b i think

step-by-step explanation:

not really sure