Me. three girls, mubanga, liseli and enala, packs biscuits in a factory. from the batch allotted
to them mubanga packs 55%, liseli 30% and enala 15%. the probability that mubanga
breaks some biscuits in a packet is 0.7 and the respective probabilities for liseli and enala are 0.2 and 0.1. what is the probability that a packet with broken biscuits found by the
checker was packed by
i. mubanga?
ii. liseli?
iii. enala?

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

answer: this is not a question

step-by-step explanation: this is a answer

well the answer to that is xoxoxo

step-by-step explanation:

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.