Prove that the two circles shown below are similar. circle c is shown with a center at negative 3, 1 and a radius of 4. circle e is shown with a center at 4,9 with a radius of 3.

Step-by-step explanation:

OK. I will prove it.

We must prove that there are two conditions:

1. The same shape (the corresponding angles are the same measure).

2. Corresponding lengths form a proportion.

1. Any two circles have the same shape.

2. We calculate the circumference of both circles.

The formula of a circumference of a circle:

r - radius

We have

Substitute:

The ratio of radiuses:

<p>The ratio of circumferences:</p><p>[tex]\dfrac{C_C}{C_E}=\dfrac{8\pi}{6\pi}=\dfrac{8}{6}=\dfrac{8:2}{6:2}=\dfrac{4}{3}" class="latex-formula" id="TexFormula4" src="https://tex.z-dn.net/?f=%5Cdfrac%7Br_C%7D%7Br_E%7D%3D%5Cdfrac%7B4%7D%7B3%7D%3C%2Fp%3E%3Cp%3EThe%20ratio%20of%20circumferences%3A%3C%2Fp%3E%3Cp%3E%5Btex%5D%5Cdfrac%7BC_C%7D%7BC_E%7D%3D%5Cdfrac%7B8%5Cpi%7D%7B6%5Cpi%7D%3D%5Cdfrac%7B8%7D%7B6%7D%3D%5Cdfrac%7B8%3A2%7D%7B6%3A2%7D%3D%5Cdfrac%7B4%7D%7B3%7D" title="\dfrac{r_C}{r_E}=\dfrac{4}{3}</p><p>The ratio of circumferences:</p><p>[tex]\dfrac{C_C}{C_E}=\dfrac{8\pi}{6\pi}=\dfrac{8}{6}=\dfrac{8:2}{6:2}=\dfrac{4}{3}">

answer is 67%

step-by-step explanation: