You are a bus driver and are scheduled to depart from terminal a at 9: 18 a. m. and arrive at terminal b at 10: 03 a. m. you arrive at a stop on your route at 9: 58 a. m., and you have 5 more stops remaining, including your arrival at terminal b. average travel time between stops is 2 minutes, and loading and unloading takes an average of 1 minute. how many minutes past your scheduled arrival time should you expect to arrive at terminal b?

9 minutes

Step-by-step explanation:

departure terminal A : 9:18 a.M

arrive terminal B : 10:03 a.M

time between B and A : 60 minutes (1 hour) - 18 minutes + 3 minutes = 45 minutes

arrive to a stop at : 9:58 a.M

time between A and stop : 58 minutes - 18 minutes = 40 minutes

5 mores tops including B

a stop - 1 stop next -2 stops next -3 stops next -4 stops next -B

average time between stops: 2 minutes

loading unloading time : 1 minute

a stop 40 minutes + (2 minutes to stop 1 + 1 minute in stop 1 )+ (2 minutes to stop 2 + 1 minute in stop 2 )+ (2 minute to stop 3 + 1 minute in stop 3 )+ (2 minutes to stop 4 + 1 minute in stop 4 )+ (2 minutes to stop B)

40 + 2 + 1 + 2 + 1 + 2+ 1 + 2+1 +2=54 minutes

real time between terminal B and A : 54 minutes

schedule time between terminal B and A : 45 minutes

minutes past scheduled time to arrive at Terminal B: 54 minutes -45 minutes=

9 minutes

(a) the volume of the cone is 20/3 in3

hence, option a is correct.

answer: 42

use a calculator to find that 845/73 = 11.575

the whole part of the answer is 11. multiply this by 73 to get 11*73 = 803.

subtract that result from 845 to get 845 - 803 = 42