Solve the following systems using substitution.
x - 9y = 25
6x - 5y = 3

x = -2, y = -3

Step-by-step explanation:

Multiply eqn1 by the LCM of 1 and 6 i.e coefficients of x

We get:

6x - 54y = 150 (eqn1)

6x - 5y = 3 (eqn2)

- 49y = 147

y = 147

-49

y = -3

Substitute y in eqn2

6x - 5(-3) = 3

6x + 15 = 3

6x = -12

x = -2

f

step-by-step explanation:

f

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3