Given that y is directly proportional to x^2 and that y=2 when x=3 find the value of y when x=6

y=4/3

y is directly proportional to x^2 is written as

introducing a constant,

y=kx^2

but from the question, when y=2 , x=3 . putting it in the formula to get the value of k

2=9k . dividing through by 9 to get the value of k

putting it in the general expression

the value of y when x=6

therefore the value of y when x=6 is

4/3

relating to or denoting a system of numbers and arithmetic based on the number ten, tenth parts, and powers of ten.

it alot will look like this 4.4