The length of a rectangle is 3 less than the width. determine how the area will change if the length of the rectangle is increased by 5 and the width is decreased by two. show your work.

At the beggining, if we called "b" to the length and "h" to the width, then the Area(A) = (h - 3) x (h) = h² - 3h.

In the final situation A = h² - 4

Step-by-step explanation:

Given A= b x h. At the beggining we have b = h -3 and h.                        So, A = (h - 3) x h ⇒ A = h² - 3h

In the second situation, b = (h - 3) + 5 and h= h - 2.

Then A= ((h - 3) + 5) x (h - 2) = (h - 3 + 5) x (h - 2) = (h + 2) x (h - 2)

⇒ A= h² - 2h + 2h - 4 ⇒ A= h² - 4.

idk

step-by-step explanation:

use that smart brain

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13