How do you find the angles of each supplementary angle when each angle has a variable (8x+6) and 12x-32?

Angle one is 88.4 and Angle two is 91.6

Step-by-step explanation:

Suplementary angles means the two angles add up to 180.

Angle one is 8x+6

Angle two is 12x-32

Angle one +Angle two =180

8x+6+12x-32=180

Simplify

20x-26=180

20x=206

x=10.3

Plug 10.3 back into 8x+6

8(10.3)+6=82.4+6=88.4

Plug 10.3 back intor 12x-32

12(10.3)-32=123.6-32=91.6

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

: )