Problem set:
at the sixth-grade school dance, there are 132 boys, 89 girls, and 14 adults.
a. write the ratio of the number of boys to the number of girls.
b. write the same ratio using another form (a: b vs. a to b).
c. write the ratio of the number of boys to the number of adults.
d. write the same ratio using another form.
*answer a-d

A: 132:89

B: 132/89

C: 66:7

D: 66/7

Step-by-step explanation:

Common sense I guess

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

idk this answer sorry cant on this one.

step-by-step explanation: