the perimeter of a rectangle is 44 m. the length is 4 m more than the twice the
width. find the dimensions.

Step-by-step explanation:

perimeter is given by

p=2L +2W

but from the expression;The length is 4 m more than the twice the width

is written as L =4+2W

putting it in the formula

p= 2(4+2W) +2W

but perimeter was given as 44m

44= 8+4w+2w

44=8+6w

44-8=6w

36=6w

dividing through by 6

w=36/6

w=6m

thus, the width is 6m

put it in the expression L =4+2W to get the length

L =4+2(6)

L=4+12

L=16m

thus the length is 16m

answer: 1,380

step-by-step explanation:

1: you turn %15 into a decimal by moving the decimal point two places to the left.

2: and then you multiply .15 by 1,200 , which will get you 180.00

3: from there you will add 180 to 1,200

4: which will get you 1,380

hope it *im kind of slow so idk if my answer is right*