In order to qualify for finals in racing event, a race car must achieve an average speed of 250km/hr on a track with a total length of 1600m. if a particular car covers the first half of the track at an average speed of 230km/hr, what minimum average speed must it have in the second half of the track in order to qualify?

The minimum average speed needed in the second half is 270 km/hr

Step-by-step explanation

We can divide the track in two parts. For the first half of the track the average speed the car achieved was 230 km/hr and we need to make sure that the average speed of the full track is 250 km/hr. Then, we can calculate the average speed of the two parts of the track and force this to be equal to 250 km/hr. In equation, defining as the average speed of the second half:

Solving for

Therefore, achieving a speed of 270 km/hr in the second half would be enough to achieve an average speed of 250 on the track.  

5 pm

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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