Find the value or values of x in the quadratic equation x2=6x-9.

x² = 6x - 9, or x² - 6x + 9 = 0, or x² - 2*x*3 + 3² = 0, or (x-3)² = 0 => x₁ = x₂ = 3.

Green eyes.

Hi Harris

x²=6x-9

First thing we need to do is

subtract 6x-9 from the booth sides

x²-(6x-9)=6x-9-(6x-9)

x²-6x+9=0

Now we gonna factor the left side

(x-3)(x-3)=0

Set factor equal 0

x-3=0 or x-3=0

x=3

I hope that's help !

understand that i don't know the answers

will someone answer his question

answer: r there any options?

step-by-step explanation: