Astorm dumps 1.0 cm of rain on a city 6 km wide and 8 km long in a 2-h period. how many metric tons (1 metric ton = 103 kg) of water fell on the city? (1 cm3 of water has a mass of 1 g = 10−3 kg.) how many gallons of water was this?

4660194 metric ton

126802560 gallon

Step-by-step explanation:

1 cm = 0.01 m

6 km = 6000 m

8 km = 8000 m

Volume = 0.01 m x 6000 m x 8000 m =  480000 m³

480000 m³ = 480000000 kg of water (density of water = 1000kg/m³)

103 kg = 1 metric ton

480000000 kg = 480000000 / 103 = 4660194 metric ton

1 m³ = 264.17 gallon

480000 m³ = 480000 x 264.172 = 126802560 gallon

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116