Suppose that, in some distant part of the universe, there is a star with four orbiting planets . one planet makes a trip around the star in 6 earth years , the second planet takes 9 earth years, the third takes 15 earth years and the fourth takes 18 earth years . suppose that at some time the planets are lined up. how many years will it take for them to all line up

90 Earth years.

Step-by-step explanation:

Analizing the information provided in the exercise, you need to find the Least Common Multiple (LCM) of the given numbers.

You can follow these steps:

1. You must descompose 6, 9, 15 and 18 into their prime factors:

2. Finally, you need to choose the commons and non commons with their greatest exponents and multiply them. Then you get:

Therefore, it will take 90 Earth years for them to all line up.

so what is the question

step-by-step explanation:

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.