In a certain city of several million people, 7.7% of the adults are unemployed. if a random sample of 300 adults in this city is selected, approximate the probability that at least 26 in the sample are unemployed. use the normal approximation to the binomial with a correction for continuity. round your answer to at least three decimal place

0.2643

Step-by-step explanation:

Given : The proportion of  adults are unemployed : p=0.077

The sample size = 300

By suing normal approximation to the binomial , we have

Now, using formula , the z-value corresponding to 26 will be :-

Using standard distribution table for z , we have

P-value=

Hence, the probability that at least 26 in the sample are unemployed  =0.2643

x^6

step-by-step explanation:

this is correct because:

x-6=0

0*x=0

so

x^6

step-by-step explanation:

f