Find the point, p, at which the line intersects the plane. x equals negative 3 minus 8 tx=−3−8t, y equals negative 6 plus 5 ty=−6+5t, z equals negative 6 minus 6 tz=−6−6t; negative 7 x plus 2 y plus 8 z equals negative 4−7x+2y+8z=−4 the point, p, at which the line intersects the plane is left parenthesis nothing comma nothing comma nothing right (simplify your answer. type an ordered triple.)

  P = (-18 5/9, 3 13/18, -17 2/3)

Step-by-step explanation:

The given point must satisfy both the equation of the line and that of the plane. We can substitute for x, y, and z in the plane's equation to get ...

  -7(-3-8t) +2(-6+5t) +8(-6-6t) = -4

  21 +56t -12 +10t -48 -48t = -4

  18t -39 = -4 . . . collect terms

  18t = 35 . . . . . . add 39

  t = 35/18 . . . . . .divide by the coefficient of t

The point is ...

  (x, y, z) = (-3-8(35/18), -6+5(35/18), -6-6(35/18))

  P = (x, y, z) = (-18 5/9, 3 13/18, -17 2/3)

c: y > - 1/6x + 1

step-by-step explanation:

dashed line - meaning this < or > also not equal

solid line - meaning this < or > also equal

your answer is c because y > means up & it's shaded up, but y < means down

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answer by yourhope:

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