Prove: if n is a positiveinteger and n2 is
divisible by 3, then n is divisible by3.

If is divisible by 3, the n is also divisible by 3.

Step-by-step explanation:

We will prove this with the help of contrapositive that is we prove that if n is not divisible by 3, then, is not divisible by 3.

Let n not be divisible by 3. Then can be written in the form of fraction , where x and y are co-prime to each other or in other words the fraction is in lowest form.

Now, squaring

Thus,

It can be clearly seen that the fraction is in lowest form.

Hence, is not divisible by 3.

Thus, by contrapositivity if is divisible by 3, the n is also divisible by 3.

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.