Agraph g consists of 7 vertices v1, . . v7. the edge {vivj} is in g if and only if |i−j| ≠ 3 or 4. draw g, and determine if it is planar. if g is planar, draw it so that none of its edges cross. if it is not planar show how it contains a subdivision of k5 or k3.3

answer: 0+0=0

step-by-step explanation:

that is the only answer that can make 0

step-by-step explanation:

here's what happens:

1) the graph of f   = x^2 is shifted 2 units to the right.

2) the resulting graph is reflected in the x-axis, so that the parabola now opens down.

3) this final result is transformed up by 5 units.

the answer is (4,3)

since the rule for r0, 90º is (-y,x) and it was already applied to form the image, all you have to do is reverse the answer using this formula.

c - they will have the same distribution

step-by-step explanation:

this is the only one that could make sense. : )