Mathematics, 13.09.2019 19:30 123martinnnnn

On a coordinate plane, parallelogram p q r s is shown. point p is at (negative 2, 5), point q is at (2, 1), point r is at (1, negative 2), and point s is at (negative 3, 2). in the diagram, sr = 4 startroot 2 endroot and qr = startroot 10 endroot. what is the perimeter of parallelogram pqrs? startroot 10 endroot units 8 startroot 2 endroot + 2 startroot 10 endroot units 16 startroot 2 endroot units 8 startroot 2 endroot + 8 units

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Answer from: pennygillbert

The perimeter of parallelogram PQRS = $2\sqrt{10}+8\sqrt{2}$ ⇒

2nd answer

Step-by-step explanation:

* Lets revise some properties of the parallelogram

- Each two opposite sides are parallel

- Each two opposite sides are equal

- Its perimeter is the twice the sum of two adjacent sides

* Lets solve the problem

∵ PQRS is a parallelogram

∵ The length of side SR is $4\sqrt{2}$

∵ The length of side QR is $\sqrt{10}$

∵ SR and RQ are two adjacent sides

∵ The perimeter of parallelogram PQRS = 2(RQ + SR)

∴ The perimeter of parallelogram PQRS = $2(\sqrt{10}+4\sqrt{2})$

∵ $2*\sqrt{10}$ = $2\sqrt{10}$

∵ $2*4\sqrt{2}$ = $8\sqrt{2}$

∴ The perimeter of parallelogram PQRS = $2\sqrt{10}+8\sqrt{2}$

Answer from: itsyogirl12

The required perimeter of parallelogram PQRS is $8\sqrt{2} + 2\sqrt{10}$ units.

Given that,

On a coordinate plane, parallelogram PQRS,

There points are P is at (-2, 5), point Q is at (2, 1), point R is at (1, -2), and point S is at (-3, 2),

Length of SR = $4\sqrt{2}$ and QR = $\sqrt{10}$ .

We have to find,

The perimeter of parallelogram PQRS.

According to the question,

The properties of the parallelogram is each two opposite sides are parallel and each two opposite sides are equal.

Its perimeter is the twice the sum of two adjacent sides

Then, PQRS is a parallelogram,

SR and RQ are two adjacent sides,

The perimeter of parallelogram PQRS = 2(RQ + SR)

The perimeter of parallelogram PQRS = $2 ( 4\sqrt{2} + \sqrt{10} )$

The, The perimeter of parallelogram PQRS = $8\sqrt{2} + 2\sqrt{10}$ .

Hence, The required perimeter of parallelogram PQRS is $8\sqrt{2} + 2\sqrt{10}$ units.

For the more information about Parallelogram click the link given below.

link.

Answer from: Quest

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

$ab^2+ac^2=bc^2$

$ab^2+ac^2=x^2$ )

triangle abd and cba are similar,

$\frac{ab}{bc}=\frac{bd}{ab}$

$ab^2=bc\cdot bd$

$25=bc\cdot bd$ (2)

triangle cad and cba are similar,

$\frac{ac}{bc}=\frac{cd}{ac}$

$ac^2=bc\cdot dc$

$7\times 7=bc\cdot dc$

$49=bc\cdot dc$ )

using (1), (2) and (3), we get

$25+49=x^2$

$74=x^2$

hence proved.

therefore option 2 is correct.

Answer from: Quest

step-by-step explanation:

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