90 ! need asap ! create a function y=f(x) that has a removable discontinuity at x=2 and a non-removable discontinuity at x=3. show work and step by step on how you got it.

step-by-step explanation:

the denominator in choice a factors to (x-2)(x+1). we have a pair of "x-2" terms that cancel leaving us with 1/(x+1). we cannot plug x = -1 into the simplified result because it leads the denominator x+1 to turn into 0.

also, we cannot plug x = 2 into p(x) for choice a either. it doesn't lead to issues for 1/(x+1) but the original function before we simplify will have x = 2 lead to a division by zero error.

a vertical asymptote is located at x = -1

the removable discontinuity happens when x = 2, so there will be a hole here.

got any answer chocies

idk

step-by-step explanation: