Find a vector equation for the line through the point p = (-3,3, -5) and parallel to the vector v= (-2,-4, -4). assume 1-(0) =-3i+ 3j - 5k. it) = enter your answer with the angle bracket notation using ''. for example, enter"" for the vector $ _ ܀

The vector equation of the line is

l(t)= "-3,3,-5" + t "-2,-4,-4", where t is a parameter.

what is the original number? you forgot to add it.

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.