The monthly demand for a product is normally distributed with mean = 700 and standard deviation = 200.
1. what is probability demand will exceed 900 units in a month?
2. what is probability demand will be less than 392 units in a month?

 a)  0.1587  b)  0.0618

Step-by-step explanation:

Let x be the random variable that  represents the monthly demand for a product.

Given : The monthly demand for a product is normally distributed with mean = 700 and standard deviation = 200.

i.e.   and  

a) Using formula , the z-value corresponds to x= 900 will be :

Now, by using the standard normal z-table , the probability demand will exceed 900 units in a month :-

Hence, the probability demand will exceed 900 units in a month=0.1587

a) Using formula , the z-value corresponds to x=  392 will be :

Now, by using the standard normal z-table , the probability demand will be less than 392 units in a month :-

Hence, the probability demand will be less than 392 units in a month = 0.0618

1/3

step-by-step explanation:

to find this, you can divide 12 by 4 which is 3 or you can multiply 4 until you reach 12 (4x3=12). both should give you 3, meaning theres three times less bananas than there are oranges.