Afrog is climbing out of a well that is 11 feet deep. the frog can climb 3 feet per hour but then it rests for an hour, during which it slips back 1 foot. how long will it take for the frog to get out of the well?

It takes the frog 7 hours to get out of the well.

Step-by-step explanation:

We know that the well is 11 feet deep and the frog can climb 3 feet per hour.

Each time it climbs, it rests for an hour, and decreases its height by 1 foot.

So, if the frog reaches 3 feet in the first hour, then in the next hour it is 2 feet.

Lets calculate with the same pattern:

1st hour: 3 feet

2nd hour: feet

3rd hour: feet

4th hour: feet

5th hour: feet

6th hour: feet

5th hour: feet

6th hour: feet

7th hour:   feet

Therefore, it takes the frog 7 hours to get out of the well.

5.5

step-by-step explanation:

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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