Assume that the number of production defects is 28 and that 14 of these are classified as major defects, 8 are classified as design defects, and 11 were neither major defects nor design defects. how many of the design defects were major?

 5

Step-by-step explanation:

Let A denotes the number of major defects and B denotes the number of design defect.

By considering the given information, we have

Now, the number of major defects or design defects:

Also,

Hence, the number of  design defects were major=5

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3