The cumulative relative frequency of the number of refrigerators sold per day the appliance store is
number of units cumulative relative frequency
0 0.2
1 0.4
2 0.5
3 0.75
4 1.00
what is the relative frequency of sales of 2 units per day?

 0.1

Step-by-step explanation:

We know that the to find the cumulative relative frequency we add all of the previous relative frequencies to the corresponding relative frequency .

Given Table :

Number of units  ( per day)           Cumulative relative frequency

             0                                              0.2

             1                                               0.4

             2                                              0.5

              3                                               0.75

             4                                                1.00

The Cumulative relative frequency  corresponds to 2 units per day = 0.5

The Cumulative relative frequency  corresponds to previous row (1 units per day) = 0.4

Now, the relative frequency of sales of 2 units per day = 0.5-0.4=0.1

Hence, the relative frequency of sales of 2 units per day =0.1

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743

first, we define the variables:

x: number of years after 1950

f (x): amount of vinyl sold.

then, with the variables defined, we have:

68594 vinyl records were sold in 1958 > f (8) = 68594

91299 vinyl records were sold in 1961 > f (11) = 91299

38720 vinyl records were sold in 1952 > f (2) = 38720

161743 vinyl records were sold in 1967 > f (17) = 161743

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step-by-step explanation: