Wthis! its a calculus question! look at the picture for the problem,

Since you mentioned calculus, perhaps you're supposed to find the area by integration.

The square is circumscribed by a circle of radius 6, so its diagonal (equal to the diameter) has length 12. The lengths of a square's side and its diagonal occur in a ratio of 1 to sqrt(2), so the square has side length 6sqrt(2). This means its sides occur on the lines and .

Let be the region bounded by the line and the circle (the rightmost blue region). The right side of the circle can be expressed in terms of as a function of :

Then the area of this circular segment is

Substitute , so that

Then the area of the entire blue region is 4 times this, a total of .

Alternatively, you can compute the area of in polar coordinates. The line becomes , while the circle is given by . The two curves intersect at , so that

so again the total area would be .

Or you can omit using calculus altogether and rely on some basic geometric facts. The region is a circular segment subtended by a central angle of radians. Then its area is

so the total area is, once again, .

An even simpler way is to subtract the area of the square from the area of the circle.

95.03 is the answer. hope this !

d. corresponding side lengths in similar triangles are proportional in length.

step-by-step explanation: