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if a container of liquid contains 60 oz of solution, what is the number of ounces of pure acid if the given solution contains the following acid concentrations?
(a) 20% (b) 25% (c) 30% (d) 50%
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(a) the amount of pure acid in 60 oz of 20% acid solution is
(type an integer or a decimal.)
(b) the amount of pure acid in 60 oz of 25% acid solution is
(type an integer or a decimal.)
oz.
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oz.
(b) the amount of pure acid in 60 oz of 30% acid solution is
(type an integer or a decimal.)
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oz.
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(b) the amount of pure acid in 60 oz of 50% acid solution is
(type an integer or a decimal.)
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(a) The amount of pure acid in 60 oz of 20% acid solution is 12 oz.

(b) The amount of pure acid in 60 oz of 25% acid solution is 15 oz.

(c) The amount of pure acid in 60 oz of 30% acid solution is 18 oz.

(d) The amount of pure acid in 60 oz of 50% acid solution is 30 oz.

Step-by-step explanation:

* Lets explain how to solve the problem

- The solution is a mixture of two or more substances

- A container of liquid contains 60 oz of solution

- The solution contains pure acid by different concentrations

- (a) 20% (b) 25% (c) 30% (d) 50%

- We want to find the number of ounces of the pure acid in each

 concentration

- Assume that the solution is 100%

- That means 100% represents 60 oz of solution

a)

- The percentage of pure acid is 20%

∵    solution     ⇒     pure acid

        100%               20%

        60                    The number of ounces

- By using cross multiplication

∴ The number of ounces =

(a) The amount of pure acid in 60 oz of 20% acid solution is 12 oz.

b)

- The percentage of pure acid is 25%

∵    solution    ⇒      pure acid

        100%               25%

        60                    The number of ounces

- By using cross multiplication

∴ The number of ounces =

(b) The amount of pure acid in 60 oz of 25% acid solution is 15oz.

c)

- The percentage of pure acid is 30%

∵    solution     ⇒     pure acid

        100%               30%

        60                    The number of ounces

- By using cross multiplication

∴ The number of ounces =

(c) The amount of pure acid in 60 oz of 30% acid solution is 18 oz.

d)

- The percentage of pure acid is 30%

∵    solution     ⇒     pure acid

        100%               50%

        60                    The number of ounces

- By using cross multiplication

∴ The number of ounces =

(d) The amount of pure acid in 60 oz of 50% acid solution is 30 oz.

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)