What are the solutions of the compound inequality 2d + 3 ≤ –11 or 3d – 9 > 15?
a. d ≤ –7 or d > 8
b. d ≤ –4 or d > 2
c. d ≤ –7 or d > 2
d. d ≤ –4 or d > 8

A. d ≤ –7 or d > 8.

Step-by-step explanation:

Given  : 2d + 3 ≤ –11 or 3d – 9 > 15.

To find : What are the solutions of the compound inequality .

Solution : We have given 2d + 3 ≤ –11 or 3d – 9 > 15.

For  2d + 3 ≤ –11

On subtracting both sides by 3

2d  ≤ –11 - 3 .

2d  ≤ –14.

On dividing both sides by 2 .

d  ≤ –7.

For  3d – 9 > 15.

On adding both sides by 9.

3d > 15 + 9 .

3d > 24 .

On dividing both sides by 3 .

d > 8 .

So, A. d ≤ –7 or d > 8.

Therefore,  A. d ≤ –7 or d > 8.

-18

step-by-step explanation:

because mean value defines that total sum value over total number of set

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